SHENZHEN I/O

SHENZHEN I/O

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30 Nov, 2016 @ 9:11pm
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Description
Those pesky blocking xbus inputs!

Not much of a difficult puzzle, but may be interesting nonetheless.
25 Comments
krtn 8 Oct, 2024 @ 4:49am 
my best. 10/433/14
s7eph4n 5 Mar, 2024 @ 11:24am 
Double checked my solution after recent posts here. Discovered that I had two unnecessary instructions. Removed those and surprisingly everything still runs smoothly. Improved to a 10/445/12
Genhis 1 Mar, 2024 @ 4:18pm 
What an annoying puzzle. :steamhappy: 10/445/13
CN- 2 Jan, 2023 @ 5:43am 
13|1040|20 and this is definitely not the way you suppose... I failed to figure out the way to find packet end, so I made a "clock thing" to generate packet end signal. Maybe I have to solve this another day.
Verdammte Heinz 30 Dec, 2021 @ 9:40am 
Nice puzzle, got 10|848|16, and 748 power with another solution, but that one takes two MC6000. Not sure yet where I can shave off those 2 instructions to reach 14
s7eph4n 14 Oct, 2021 @ 2:30pm 
I went to the following phases:
- ez pz lemon squeezy
- wait a minute, y u no stop?
- impossibru!
- brain.exe stopped working
- holy moly ... yes ... that should work
- I need only ONE more line
- ok, restructure ... optimize
- yes ... Yes ... YES
- GOT IT ... 10/544/14
- noice one, like very much

Good job. Thx for that.
jek777 24 Jun, 2021 @ 2:13am 
Fun and different kind of problem (compare to builtin levels at least, this is my first workshop one). Got 10/962/17 for those who care. ( I haven't really tried optimizing, I mostly enjoy just solving the task, with few components, but don't care much for power or lines, there is enough optimising needed just to fit the lines in the processors :-) )
harry 3 Jun, 2021 @ 10:00pm 
haha, excellent idea
Smoke Fumus 24 Sep, 2020 @ 2:44pm 
@DarkRedman666 You can use other methods of signalling. Such as reading if array value has changed in a loop. Come on, it's not that hard.
Eisenhorn 20 Oct, 2019 @ 11:20am 
Cool! My result: 10|557|14. I can optimize a little more, but laziness :lunar2019piginablanket: