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SHENZHEN I/O >  Workshop > shigawire's Workshop > DIV 2
DIV 2
Description Discussions0 Comments9 Change Notes
9 Comments
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Moose 6 Jun @ 9:34pm 
My solution: https://steamproxy-script.pipiskins.com/sharedfiles/filedetails/?id=3494555087
Moose 6 Jun @ 9:30pm 
Got 8/705/19 trivially, I suspect you can use dst to increase throughput but it remains to be seen whether its actually more efficient giventhe pre-processing necessary
NoobDancer100 2 Jun @ 7:56am 
I got 8/70.6k/15 not particually good (especially compared to other people) but easy to understand solution.
Verdammte Heinz 6 Nov, 2024 @ 11:34am 
Optimized the low power version for costs to 8 / 705 / 19 . As I could not optimize it further checked the solution from Shigawire, nice one! I only considered taking two lowest digits and multiply those at the same time, but did not think about taking the two higher ones.
Verdammte Heinz 5 Nov, 2024 @ 7:57pm 
Solved in 6 / 70603 / 12 and 10 / 668 / 18
Scoptlie 14 Oct, 2024 @ 8:33am 
@shigawire Oh that's a very clever way to do it! Using the simple IO pin basically for extra storage is something I wish I had considered as I was stuck on eliminating the need for the dat register . I much appreciate your sharing, and thanks for the fun puzzle.
shigawire  [author] 11 Oct, 2024 @ 7:21am 
@Scoptlie : Mostly it relies on using simple IO to make sharing intermediate values cheap between 2 MC4000s. and that the instructions:
mov <src> acc
dgt 0
can be replaced with
dst 0 <src>
if you know that acc is less than 10

(Screenshot of the 6/631/17 solution )
Scoptlie 9 Oct, 2024 @ 12:05pm 
This one is driving me mad. The best I can manage after many attempts is 8/705/19 . I'd be curious to see the 6/631/17 solution.
shigawire  [author] 26 Sep, 2024 @ 7:45am 
So far I have 6/631/17 or 6/50511/13